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1.                                                                       874 574 579  sz  vel       veel 583  584  585  585  see  ser  588  588  583  589  53  53         53  532         533  533  533  534  534  534  534  535  535  535  sas  535  sss  535  596  sas  535   854      seel 558  vel 582  veel see  ver ses         572 524  570  624 579  so  58             ses  584  ses  585  seel ser  verl see  588  ses  vas       53  53  sof 53  53         53           528  53  534       54  543  546  549  551  554  556  558  sei 583  565  ser  seel 52  572  523  575  szef 621 528  579  Gel vol 582  583  583  584  584  585  ses  585  586  see  586  586  see  sos  soe      ie 52  sos  voel 631 5 35  Bas  542        sae vel 553  ssel 558  58         voe see  see 57  571      524  575  szef 577  szef szol 579  sel sal sal sel sed      582  see    es  485   3  496  el 505  51 siel sisl 523  521 531  sos  538  542  545  548  551  553  556  558  Ge         564  seel ser  ses 67  szi s72 573  524  575          e    5 77  n  577          Lese           469  75      ser        see       soe       s1 522  525  83 saf 538         544  sarf Ge  553  seel      559  581  563  564  566         seel ses       sr  74         522  573  533  573  e a ER EER               Ee      eee ee EET             od      dis od ed ee           a  szef saal veel e       deel ezel 4 79  sel 432  sel 503  sos  sif sie  523  527  sa 535  538  541 44  ser  549       553  555  551  558  Ge  vol seel        ses  564  564 
2.      ww   AU                     m                je je  gt              oo     eo            LY              A          s           dm          n   n   n   m   n       n      gt  m             TEL  MIS                      gt         gt  fem Fer Ferm Va ji     rm Jo Ja    fe  o    j                          moo    a              gt  je je fe fe fJ   in  um le Jo fin  2           de Fo Feo  gt  fe fe  Ale el fio fio  2         jae ja Fo fe fe Fo  m fin le  e fio Ie   gt              gt         fje    gt  Fo je fe fe  io jo    Jo le        gt                 ar   gt  aki                        IE  2 ol              eR         1 5         aa fo     C                    val 13  13  13  12  12  12    1 4    1 4    2  12     13  4  13  EP  EP  EP  H    14    Ge 3      Figure 7  Completed calculation of head distribution    Contours of constant head can be interpolated from the results shown in Figure 7  For a contour  spacing  head drop  of 0 5 m  the equipotentials from the FDM spreadsheet can be compared to  those drawn using the flow net sketching method outlined in the main text  Figure 2 8   These  are shown in Figure 8  from which it will be seen that both methods give an almost identical    solution to the location of the equipotentials     The flow lines could then be drawn in to give    curvilinear squares if necessary  however it 1s possible to determine the amount of seepage from  the change in head along the discharge boundary without drawing flow lines     Seepage   8
3.     EE ME EE             ME    EE ME EE EE    EE SE EE    SE EE ME EE ME      EE         20 10  10 5    Figure 3  Data entry    The FD mesh may now be assembled  As in the example from the main text  the soil domain  extends approximately 8 m either side of the sheet piling  This requires 17 nodes  at 0 5 m  spacing  from one edge of the soil domain up to and including the nodes along one side of the  sheet piling  As the pressures head along either side of the wall may be different  nodes are  required for both sides of the piling  even though it has a negligible thickness  A total of 34  nodes will therefore be required horizontally  i e  34 columns   18 nodes are required vertically  to model the 8 5 m depth of soil  1 e  18 rows      The uppermost nodes  representing the upper surface of the soil  represent the recharge  left  hand side  and discharge  right hand side  boundaries  Values of head  relative to the datum   are known at these nodes and are entered in metres as shown in Figure 4     The left and right boundaries are then formed by copying the formulae for these boundary  conditions from the FDM node library to the drawing area  i e  LB and RB respectively   Note  that of the 18 nodes required on this boundary  the top node is on the discharge boundary  value    0 5 m  and the bottom node will be part of both the right boundary and the bottom boundary   i e  a bottom right corner  BRC   Only the 16 nodes in between should therefore have the RB    5    Seepage  
4.    334  343  364                         423  432  ner sasl         63           ezel azo  seal         ssl        495         e  s         228 225  225  225  225  225  225  225  22e  22e  244  262  229  296           aze  asf ar       389  3985  soel sil 420   34  442  45  ne           seel 473  ezel sei nos  seel sol ese  434  435  436 436           EM 44 sisse EEE MB eene ee er rd ed ed eed ed e e n  Mi ML  pe po pe Po             pope pe poi po pei po pe pe pri pn sar   eo  EE EE eee li               PP PP PP EE EIE EF  BEER DE                    pepe               pe prp        EIS ES      ESE  1 A      us vas ves  veel 203  224 24 251 224  23  soel sal 334  347  se  322  383  334  eo  evo  sai 425  435  443  449  asel 455  ses  ser       azal 475  477  ezel          473   02  025  oze zel oss  14 ve  veel 182       22  23e 255  222  288  soo  sil     4 345  ase seol sod as eod 41        427  ese  e ser  452        sei ses                  ezel ee  477  477            os Lora         vel vas ve  vel vos  21  238  253  21 288        sif aal 343  356  see  374 sa                    420  32  aof 445  ssil sel sel seal ner  42           szal ezel szef 476   025  028  os       oss  i  138  159        198  211 26  252  269  285  3       329  s42                aze  83  338   08  eve   24   3   38   44  45  455  459       seel  69  azi 23  szal ezel 475   025  oss  ozzl oss  wl 138  153  179  ese  or  23  252  269  285  ol ave  323  342  ssal ses  aze           ssel 07  446    
5.   8  User s Manual             Flow net sketch   Fig  2 8  main text                 spreadsheet       E ya    Figure 8  Comparison of FDM equipotentials with flow net sketch    6  The flow of pore water must become perpendicular to the discharge boundary as the fluid  approaches the boundary  Each set of vertical nodes in this region therefore represent flow  lines  The change in head  Ah  at the discharge boundary is therefore found at a given distance  from the right edge of the wall as by entering the formula shown in Figure 9  This is then  copied as shown     Total head  h  m      05 05 05 m    0 7    5  05        oz  ol oz  il ali e  os  03  os  al al al         EE ER Tu  EE  TT ENER ENER ETE ENER EE EE ET EP ET          rr RPP EE EP EP         te D EP EP EREM EE EE ER ET   5             gt     5  25                      TELE          EE ER ER EE Er EE Ee En       Copied              Figure 9  Calculation of flow rate    Seepage   8  8  User s Manual    The average amount of flow within the flow tube between each set of adjacent flow lines is then  found by entering the formula shown in Figure 10     Total head  h  m      45 45 45 45 45 45 45 45 45 45 45 45 45 45 45 45 45     05  05  05  05  05  05  05  05  05 05  0 5  05  05  05  05  0 5         saf aal       al aal saf ET ET ET ET EY sal ET ET aal ala                            FE FEET PE           FESTER  m  Ol cal aah      acl al 1444444  saf EEEEEEEREEE _    Bidet eee cM FEEEEEEEEEEEEEE         ss es faa aad al of
6.   a  oe  oel os        osf os                     1121414    58           131 13  13  12 12  1                             7 sof ssf EP uf ul al al I 14            a va  sahna  1          1       EE   St                             12  12  12  12     25       Ey EP En EV Er EVEN ES EV ETB FPES E    a    EREDNEEPEREPETEPEPETEPETEPETET      2 PRETENEEPETETETETEPETETETETETET  37 2 EREREEETETETETETETETEY 13  13  13  13  13  EE EE EE E E E EE EE 25  25  23  22  al 19  18  17  18  15  15  14  14  13  131 13  131 13       011 01  0 1 01  01  041  01  041  041 04  041 01  01  04  01  04  0 1  01  01  011 01  0 1  01  0 1  DA 04  01  0 1  0 1  01  0 1     sunicanze 8628        Figure 11  Calculation of flow rate  contd      9    Seepage CSMS8  User s Manual    Performing the calculations gives ZAA   1 4  The flow rate  4  can then be found as described in  Section 2 7 Example 2 3 of the main text     q k         This gives q   1 4k  which compares favourably to the value of q   1 5k found from the flow net sketch  in Section 2 4 of the main text     It can readily be seen by this example that use of the FDM in this way provides a very quick and simple  way to determine total head  and hence pore pressures if necessary  and flow quantities for a seepage  problem  and is less subjective than the sketching of a flow net     4  APPLICATION TO WORKED EXAMPLES IN MAIN TEXT    This section demonstrates how the FDM spreadsheet may be applied to the other worked examples  included in Chapter 2
7.   for nodes on the boundary of an  impermeable element  e g  some sheet piling or the bottom of a foundation  some of the adjacent cells  will be inactive  e g     within    the impermeable boundary   As a result  special versions of the basic  node formula  Equation 2 31 from the main text  are required to correctly model the boundary  conditions within the model  The formulae employed are described in more detail in Section 5 of this  manual  The FDM node library section contains one example of each formula  which may be copied  into appropriate cells in the Drawing area  see below  to build up a complete FD mesh  An example  of this is provided in Section 3  The drawing area may be extended if necessary by inserting additional  columns between columns BQ and BR and inserting additional rows after row 57  This may be  necessary for problems in which a fine grid spacing is required to give a high level of detail in a large  problem     The Depth scale section auto calculates the depth in metres of each row of nodes using the grid  spacing entered in Basic data  The depth scale fixes zero at the level of the uppermost row of nodes  used in the problem  The uppermost row of nodes should therefore be entered in row 7 within the  drawing area  The examples in Section 4 include problems where soil levels may be unequal within the  problem  e g  for an exacavtion  for guidance  This section also uses the input datum level to provide  an alterantive scale which 1s the elevation hea
8.  23    Seepage   8  8  User s Manual    Node Elevation above                index Depth Datum  z  0 0 6 6 6       6 6 6 6 6 6 6    6       6 6    6 6 6 6 6 6 6 66 6 6 6 6 6    6 6 6 6 6 6 6 6 6  1 0 25 5 75   o of of of of of o E  2 0 5 55 E E E   o   o          3 0 75 5 25   o of of of of of o  411 5   of op o ol of       5 125 4 75   of of of of of of o  6 15 45 E E E   o              7 175 4 25   o of of of of of o     2      of of ol of of ol o  3 2 25 3 75   of of ol of of of of        o  o  10 25 35   of of ol ol of of of o TE  1 2 75 3 25   of of of of of o   o o  20    op ol s of d of o  ol       13 3 25 2 75   of of of of o of     14 35 25      15 3 75 2 25  16 4 2  17 4 25 1 75  18 45 15  19 4 75 125  20 5 1  21 5 25 0 75    22 5 5 0 5             23 55 025 Gol o o oj o o o o ol of o ol ol o ol ol o o ol o o ol oj o o  ER E         D EE T      EE            ER E DT MY      EST           D GT Y EP EST         DT      UT ET EE    2       24 6 0    Figure 25  Example 11 5b  section              6                                                                   6                                         AE PRR    AE EE EE EE    se  55  55  55  55  sof 55  ssi 55  ssi 55668  s52 553  554  555  557  558  Gel 563  565  ser ses               524  575  szef 528  szal 529  58  58              583  583  583  583  583          EER ee re         A rer prp ES EE ER ee Ee      Fee  Eos 5   el sol sol sol sol sol sol BOM        sos          506  509  sel 5   52  525  53 534  538  5
9.  45  45  4 5 45  45  45  45  45  45  45  45 49105 51 5051 051 151 051095  95195           051 051 151 051 Dat 05  iE di Em    jg     o       E yuo   ia    0 dto Er  gio En  dio Bir   alo   te  dio EE  Lg yuo   ie                E dr gl Upper Right Pile  URP  ol  m   m  _ el Intermediate Right Pile  IRP  Lig      j        i         d a ay    oj of ol ol ol of of ol od of of ol ol of of ol A of of ol ol of of ol ol of of ol of of of of of o    Bottom Right Pile  BRP     Figure 5  Assembly of model  contd      4  The remaining nodes in the interior of the soil body on either side of the wall are then filled  using the generic    INTERNAL CELL    formula  1   as shown in Figure 6     Mode Elevation above  index Depth Datum  z    0 0  0 5  1 05 E  2 1 45  3   15 2  4 2 25  5 25  3  6 3  3 5  7  35  4  8 4 45  9 45 5  10 5 55  11   55     12 6 6 5  13 65 7  14    7 75  15   75 8  15 8 85  17 85 9  18 9 9 5    Total head  h          Seepage   8  8  User s Manual    4 5  45  4 51 45  45  45  45  45  45 45  45 do  45  45  45 45  45  05  0 51 05  Do  05  0 51 05  0 51 05  0 51 05  0 51 05  0 51 0 5  0 5  0 5       Figure 6  Assembly of model  contd      5  Pressing F9 on the keyboard will then start the iterative calculation  The numbers in the cells  will initially change rapidly  this change will slow down as the calculations converge to the  solution shown in Figure 7  Once the calculation is complete  the numbers in the cells represent  the values of head     at a particular point 
10.  555  565          ER ER PEPERIT PSP                    OE        pego             ER EERS                 FEE FEES      EIE   4 22  ses  asal vol       33  s42  as    sel ser  24  seil seel ssl 5  voe   r  sif G2  524 soe  532  525  sae  sa        546  548  543  55  552  seed 55  ssel 556  557  551  552  227  as  ssa aza  385       sor  ave  ezel 437  447  sel          azi ezel 485          sel 503  508  sil    522  526  529  533  536  528  sai 543                548  Ge  55  552  553  553  553  553  as    sool su sa os ssal              ees aze  esl ss         sool                 sie  52 524  voel sai 524 527 539  541 543  548  546  542  548  543  55  55  ss    28  soe        338  349         aze  ses         412   23  sol 443   52  sel          ezel ssl ves   35  soi soel snf sil su  523  vor 531 533  535         539  541  543  544  545  sae  546  542                 sel 375  seel 4      23  433  saal a52  sel seel ezel neo  89  asel 50  oe Gal            522 525  24 520  534  536  538  54  54  542  543         544  544   244  262  28  238    ve  aal                       ses  sod sisl 424  sas  44         62           477   84  ssl 436  sol soel Gul sre  519  522  525  528  531 533  535  sar  538  533  54  54  sel       ass  a  233          sel 379      2 sos          427  sarl asr  455  asal      azal seo         asr  soo         sel sis 522  525  528  53  s32  534  535  521  538  538  539  538   138  22  242  263  284  3031 sai asel 354  ses  asa  336  sos  42         
11.  8  8  User s Manual    formula copied in  The left boundary and bottom boundary  BB  can similarly be copied in as  shown in Figure 4               Bottom Left Comer Bottom Right Corner   BLO   BRC     Figure 4  Assembly of model    3  The nodes on either side of the sheet piling can similarly be incorporated using LB and RB  nodes as shown in Figure 5  The nodes beneath the sheet piling are a special case  as due to the  small thickness of the sheet pile wall  the nodes below each side of the sheet piling essentially  represent the same point within the soil and so require special formulae to ensure that the heads  calculated at these nodes will be consistent  These formulae are given in the central column of  the node library     NODES AROUND  amp  BENEATH PILING      The nodes at the toe of the  wall  i e  at 6 m depth  are represented by Upper Right Pile  URP  and Upper Left Pile  ULP   on the right and left sides of the wall respectively  The nodes below this are modelled using the  intermediate nodes  IRP and ILP  and those on the bottom boundary using the BRP and BLP  nodes  Further details on the formulation of these FDM nodes are given in Section 5     Node Elevation above  index Depth Datum  z    0 0  0 5  0 5  1  1  1 5  2 5  2  2  2 5   3  3  3 5  3 5  4          ON  gt   ho  en    4  4 5  45  5  10 5  5 5  11 53  6  12 6  6 5  13 5 5  7  14 7  7 5  15 75  8  1   8  8 5  17 8 5  9  18 9  9 5    Total head           Sheet piling   indicative    45  45  45  45  45 
12.  al ol of of of               oof oe oo os  osf os       osl          PEFENENEEEFEEEEBE cal ch cal cal cl al a od aad ol coal cal cl call   E     EE EE HEE WE a EP EP EF s Ee Er                                          ae Eed       E 39 EB       38     sal cal sal aah sal sl ard ool aol ol oad eal acl cl oc E ph  38  32  sel 38  sel 37  32  37  sel ss  35  34       32        3  29  2  Ev EET Er EY EV ETEM ET ET ETER EE EN dad EE EE  E                                          TEE    041  D1  01  01  01  01j  04  DA  OFT  04  01  DA  041  04  0 1  04  DA                    127     27     Copied    Figure 10  Calculation of flow rate  contd      Finally  the change in head within all of the flow tubes is added together to give           as  shown in Figure 11  Once this last formula has been entered  F9 must be pressed on the  keyboard to perform all of the calculations entered during this step     Total head  h  m      45 45 45 45 45 45 45 45 45 45 45 45 45 45 45 45 45   0 5  05  0 5  05  05  05  0 5  0 55  05  05  05  05  05  0 5  05  0 5   ES      rs and       08  os  os  os  os  os  os  os  os        asl os  os    l a 3 OG oz        02  02  ozl oz  02  02  02  oz 02  02  os        os  os  os  43        43        43        aal 42  42  42  42    2    2  42    2  42  42      quum mmm _          seien en edem enl col        m oof vel ve os  08  os     ET sa  saf saf saf aal sal sa  sal ol a  al ah al ol eh al    a   4 al a af os  ET af aif aa EE EE EE EE EE EE ET ET eb s ul a   
13.  e how to model problems with layered soils     Zero depth is set at ground level on the right hand side of the model and the datum is set at 6 m depth   i e  the water level in the excavation   A grid spacing of   m is used  giving the FDM node layout  shown in Figure 21  Note that the equivalent isotropic permeabilities of the upper and lower soil  layers must be entered      the    kr and    k     cells respectively in the Basic Data section BEFORE    15    Seepage   8  8  User s Manual    any calculation is attempted  The current version of Flownet CSMS only supports two distinct soil  layers                 6 00m                             8 00m                 HEIL          H             CU ER ER m C  aus a                  0000000900000 068                 a    20000             HH      0 1 2 3 4 5 10                                    Figure 20  Example 2 3  section          ld                 ey            m m im le         ww      nnn    Figure 21  FDM node allocation  Example 2 3    16    Seepage CSMS  User s Manual    The resulting values of head may be found in the in the appropriate worksheet within  Seepage CSMS xls  The values of head may be extracted from the nodes representing the tunnel walls  and the method described in the previous example may be used to convert these values into pore  pressures  The resulting pore pressure distribution is shown in Figure 22     100  80  60  40          20 40 60 80 100    100 80 60 40 20 0    Figure 22  Pore pressure dis
14.  of the main text  These are included as complete worksheets within  Seepage CSMS xls  Note that this implementation of the FDM is not suited to problems involving  unconfined seepage  e g  flow through embankment dams   As such  only Examples 2 1     2 3 will be  considered here  These examples will demonstrate the use of the full range of nodal formulations  included in the FDM node library  including applications to sheet piling  layered soils and buried  Structures     Example 2 1     Flow into a cofferdam    The problem geometry is shown in Figure 12  This problem is similar to the worked example in  Section 3  however  it demonstrates     e how to tackle problems with varying ground level   e how to tackle problems involving symmetry   e how to extract hydraulic gradient information from the FDM     The soil domain is assumed to extend 8 m on either side of the excavation  Zero depth is set at the    level of the soil outside the excavation and the datum is set at 2 5 m depth  1 e  the water level within  the excavation   A grid spacing of 0 5 m is used  giving the FDM node layout shown in Figure 13     10    Seepage   8  8  User s Manual          5 50 m        Sheet i  2 50 m piling    Plane of _  Z       symmetry  2 00 m      Datum  6 00 m    i    2 2bm  0 12 3 45 10m  TT TT dt E    Figure 12  Example 2 1  section     45 45 45 45 45 45 45 45 45 45 45 45 45 45 45 45 45 4 5 4 5 45 45 45 45 45 45 45 4 5 45 45 4 5 45 45 45 45       Figure 13  FDM node allocation  Example 
15. 2 1    The resulting head distribution within the model may be found in the appropriate worksheet within  Seepage CSMS xls  It will be seen that the solution is symmetric and validates the symmetry  assumptions made in the main text when sketching the flow net  A half FDM model could equally well  have been used  which would have given the same solution     Equipotentials have been derived from head distribution and are compared with those obtained from  the flow net sketch in the main text in Figure 14     11    Seepage CSMS8  User s Manual    Flow net sketch       _7  AS    Figure 14  Comparison of FDM  left  and flow net sketch  right     FDM    XK                                 ya            m      gt          mm   lt  7              wu       v        s                             p       4     7 1              d  MEE             The hydraulic gradient immediately below the excavated surface is found using the change in head  between the nodes just below the surface and the discharge boundary towards the centre of the  excavation  This can be determined as in Section 3  giving Ah   0 26 m  This drop in head occurs  between two adjacent nodes which are 0 5 m apart  grid spacing   so As   0 5 m  Therefore  i   Ah As    0 52 which compares favourably with the value of 0 5 derived from the flow net sketch in the main  text     Example 2 2     seepage beneath a dam spillway  The problem geometry is shown in Figure 15  This problem demonstrates     e how to incorporate an impe
16. 24             444  eel 455  453  463  seel               473          475  475          Figure 26  Example 11 5b  contd      24    
17. 42  sae  548  551 553  558  558  553  sei 562  564  ser  nos  566  ser  ser  ser  se  Mid eee ee ee eee ee mi uico     Mum                le   al e lal a  ula u     425  425    ae 420    zel 425  42e  sze   28  sze   21 427  ezel 429  43  422        ese  sel      sel seel          sol        sif sel 52  525  528         534  536  538  54  sai sel 543  544  544  saa  Eos af sol sol so sol sod sol dol      4 024 s02  soz   02 soal ooh 4  25  sai 454       azal sol seo   95  sol sos sr sil sis  522  525  528  53 s32  533  sos  sae 526  53         Lage  325  37e                  276         szef        aze zel               aze  szef asl      en  ezel saf        ee       err oe  3  sel 502  sos saf       sr  52  522  524  526  521  523    24 53  53  29  38 sel sel sel      351 see  383  333  eve  427  439  49          ar  azal       aar 433  sarf sool soe  sos 512  sis sv  sis  52 522  523  523  523  aas 224  225          24  sa sel         224      sel azo  so C7 EP asel         sasl sool     vae sasl aas        vee 474 474 voe ses sof ese  soo or  ERIT EP EP sel rl                 EF 43        arr  333  349  ses  sel ass   06         29  saol 448   56                azel sez  aar           sel 433  502  soe soe  508  sos 81       su       Lage  275  274  275         275  225  215  225  215  275  276  253  sos  ozel                  85  398   1  42   3  sel ssel ssel  63  469  475  eel  85  seol           36  ssel 8 sool soe soe  505  soe  25 25  25  25  25 oes  286             
18. Left Pile zs h   ILP       Bottom Left Pile   BLP     Upper Right Pile   URP        Intermediate     Right Pile z h   IRP  A    Bottom Right  Pile   BRP        19    Seepage   8  8  User s Manual    Node type Governing equation   Representation in node library    Bottom Right  Re entrant   BRR     Bottom Left  Re entrant   BLR     Upper Left  Re entrant   ULR     Upper Right  Re entrant   URR     h   h   2h   2h   h     6    h   2h  2h   h   h     h    6    Ah  h   h   2hy   i 6    h   h  h    2h    2h   i 6       20    Seepage   8  8  User s Manual           Representation in node  h gt       nternal cell     h Ah  h  Ah    Layered     p  ovo      IL           Right  Boundary       Ah    2h  As ha  Layered 4   RBL       Left  Boundary    2h                 Layered 4   LBL        Upper Left hy Es  5 h   A               Pile  Layered     N  Fe 2 3  4214     ULPL     Upper Right  Pile  Layered   URPL        Intermediate   Left Pile       hy  A hy  h    Aha  Layered T   4   ILPL        h    Intermediate   Right Pile  h    Ah   h  Ash     pa 12 3 24  Layered   4   IRPL  C            kk  2 ktk    21    Seepage   8  8  User s Manual    APPENDIX    This appendix demonstrates the use of Seepage CSMS xls for analysing the drained backfill in the  retaining wall problem of Example 11 5  This problem demonstrates     e how to incorporate a linear drain within models    e how to determine the resultant pore water pressure thrust on a plane within the soil  for use in  the Coulomb wedge m
19. Seepage_CSM8    A spreadsheet tool implementing the Finite Difference Method  FDM  for the solution of two   dimensional steady state seepage problems     USER   S MANUAL    J  A  Knappett  2012     This user s manual and its associated spreadsheet     Flownet_CSM8 xls     accompanies Craig   s Soil  Mechnics  8  Edition  J A  Knappett  amp         Craig      The spreadsheet  Flownet CSM8    is an implementation of the methodology outlined in  Williams   B P   Smyrell  A G  and Lewis  P J   1993  Flownet diagrams     the use of finite differences and a  spreadsheet to determine potential heads  Ground Engineering  25 5   32 8     Seepage CSMS8  User s Manual    1  INTRODUCTION    This manual will explain how to use the spreadsheet analysis tool    Seepage CSMS xls  to solve a wide  range of two dimensional steady state seepage problems  This spreadsheet is an implementation of the  Finite Difference Method  FDM  described in Section 2 7 of the main text  Spreadsheets offer a  number of advantages for solving such problems  namely     e The tabular layout is particularly suited for forming a two dimensional mesh  in which each cell  represents a node of the mesh  The problem as laid out on screen will therefore bear a strong  visual resemblance to the problem being addressed    e As the total head at each node depends on the values of the nodes around it  it is required to  solve a large number of simultaneous equations  This can be done effectively and efficiently  using the 
20. The distance along the slip plane from one orange cell to the next is found by Pythagoras    Theorem   one cell across   0 25 m  two up   0 5 m so AL   0 56 m   The values of h and z can then be extracted  for each orange cell  the pore water pressure at each point is then found using Equation 2 1  These  values are then numerically integrated along the slip plane using the trapezium rule  to give U   36 8  kN m  per metre length     Example 11 5 b   sloping drain behind retaining wall    The sloping drain in Example 11 5 b  is modelled in the same way  except that the cells representing  the drain now fall on a 45   line as shown in Figure 25  The left hand boundary is now impermeable   representing the back of the concrete retaining wall  starting from the bottom left hand corner the  internal cells within the mesh are replaced with the value of elevation head in each row     The calculation then proceeds as normal by pressing F9  The resultant pore water thrust is to be found  along the same plane as before  Starting from the bottom left hand corner  a point close to the failure  plane is found by going up two cells for every one across  These cells are highlighted in dark orange in  Figure 26     The values of hand z can then be extracted for each orange cell  the pore water pressure at each point is    then found using Equation 2 1  These values are then numerically integrated along the slip plane using  the trapezium rule  to give U   0 43 kN m   0  per metre length    
21. d  z  above the datum  Note that positive values of z  indicate nodes which are above the datum     As the elevation head is the same for all nodes within a row  the worksheet provides the user with both  values of h  by calculation     see Section 3  and z at all nodes within the model  The distribution of    3    Seepage CSMS8  User s Manual    pore pressure within the model can therefore be obtained by application of Equation 2 1 from the main  text at each node  This may be efficiently conducted for a given problem using the remaining cells in  the worksheet as necessary     The workbook Seepage CSMS xls contains a series of worksheets which are named as shown below     New analysis     Example 2 1   Example 2 2   Example 2 3   Example 2 5  Lw Lb 0   Example 2 5  Lw 9 1   Example 2 5  Lb 9 1   Example 11 5a   Example 11 5b    Each of these worksheets has the structure described previously  though in all cases except    New  analysis       a completed solution is presented  the    New analysis       sheet having been used in each  case to analyse a worked example from the main text   The use of the    New analysis       sheet to solve  a seepage problem will be described in Section 3 of this manual  the remaining sheets will be discussed  in Section 4     2    3  WORKED EXAMPLE    To illustrate how the FD mesh is assembled and analysed  this section will consider the example  presented in Section 2 4 of the main text  which was used to describe the flow net sketching techn
22. delling of drains within a body of soil  with reference to the  backfilled retaining wall problem in Example 11 5     2  PROGRAMME DESCRIPTION    The spreadsheet analysis tool essentially consists of a single worksheet in which all calculations are  conducted and which contains all of the necessary information for solving a problem by the FDM  The  worksheet consists of four sections  as shown schematically in Figure 1     Seepage CSMS8  User s Manual    FDM node    Drawing area                                           ER      GEN m    Depth scale       Figure 1  Worksheet structure    The Basic data section contains cells for user input data  including the spacing between nodes  a  square grid with uniform spacing in both horizontal and vertical spacing is implemented in the current  version of the software   the depth at which the datum for head measurement has been selected  and  cells for inputting permeability if layered soils are to be modelled with different isotropic  permeabilities  k    ko   Note that for problems in which only a single layer of soil is present  the head  distribution 1s independent of the permeability of the soil  and the permeability cells may be left blank   The spreadsheet may also be used to analyse problems with anisotropic soils by using equivalent  isotropic permeabilities  K   K       Below the Basic data section is the FDM node library  As the formulation of the basic equation  governing the head at any node depends on the cells around it
23. ethod of analysis  Section 11 5      Only the retained soil is modelled in this case  assuming that the underlying soil is relatively  impermeable   Zero depth is set at the top of the retained soil and the datum is set at 6 m depth  i e  the  bottom of the retained soil   The head along the top surface of the soil is therefore 6 m  pore pressure      0  elevation 2 6 m   A grid spacing of 0 25 m is used     Example 11 5 a   vertical drain behind retaining wall    The upper  right hand side and bottom boundaries are set as before  The drain is vertical and runs  along the back of the retaining wall  Within the drain the pore pressure must always be zero  so the  head will always be equal to the elevation head  1 e  is independent of the adjacent cells   This can be  modelled by setting each of the cells on the left hand boundary equal to the value of elevation in that  row  giving the FDM node layout shown in Figure 23                 2        e  m     E       ho    Figure    3  Example 11 5a  section     The calculation then proceeds as normal by pressing F9  For the Coulomb wedge analysis  the  resultant pore water thrust along a plane inclined at 6   45   0 2   64   to the horizontal is to be found   Starting from the bottom left hand corner  a point close to the failure plane is found by going up two  cells for every one across  These cells are highlighted in dark orange in Figure 24     22    Seepage   8  8  User s Manual    6 6 6                                         
24. he underside of the spillway may be copied out  The elevation  head  z  from column Z for each node may then be used to determine the uplift pressures acting on the  spillway using Equation 2 1 from the main text     u  y  h z     This method may similarly be applied for the nodes along either side of the sheet piling to determine  the net pore pressures acting on the piling  Note that this is the same method used in the main text   however  the FDM is particularly suitable for this application as the heads are automatically determined  at the same points along each side of the wall  The uplift pressure distribution on the underside of the  spillway and the net pore pressures on the sheet piling are compared with those determined from the  flow net sketch  main text  in Figures 18 and 19 respectively     Seepage CSMS  User s Manual    Distance from downstream end  m     0 5 10 15  0     9    Flownet sketch     O    Finite Difference             O o    Uplift pressure  kN m                40  50  60  Figure 18  Comparison of uplift pressures on spillway  Net fluid pressure  kN m    0 10 20 30   2         3  e    9    Flownet sketch       4    O    Finite Difference   gt   D      5   6    Figure 19  Comparison of net pore  fluid  pressures on sheet piling    Example 2 3     Excavation next to buried tunnel in layered soil  The problem geometry is shown in Figure 20  This problem demonstrates     e how to incorporate an impermeable structural element which is completely buried  
25. igue   The example is shown in Figure 2  The steps required to solve the problem are illustrated below        0 1 2 3 4 5 10m                                     Figure 2  Example problem  section     4    Seepage   8  8  User s Manual    1  For this problem a grid spacing of 0 5 m is selected  This means that almost all of the  dimensions in Figure 2 can be represented exactly by whole numbers of nodes  The depth of  8 6 m between the soil surface and the lower impermeable layer will here be approximated as  8 5 m  which is expected to have a negligible influence on the resulting seepage  The value of  0 5 is entered into the grid spacing cell in the Basic data section as shown in Figure 3  As in the  main text  the datum will be selected at  0 5 m depth  i e  the downstream water level      The spreadsheet is programmed to calculate the results of formulae only when requested by the  user  After entering the grid spacing and datum level  pressing F9 will calculate the depth scale  and elevation heads in the Depth scale section     Depth scale    Node Elevation above  index Depth Datum  z    Total head  h  m      BOUNDARIES BETWEEN SOIL LAYERS    EE                               mE  EEN  P  givin                   CO          A                   ho  ha  ei             vo     EE     gt                        ao                 U N     O  co      e ea LR       co  4 e Un  n           Midi        2  wo            A  e    BOTTOM SURFACE     gt         Lm  e  b  mm mm mm mm ME   
26. iterative calculation techniques embedded within modern spreadsheets    e Spreadsheet software is a standard component of most suites of office applications which are  installed as standard on most computers  e g  Microsoft Excel  within the Microsoft Office  suite  or Calc  within the Open Office suite   They are therefore almost universally accessible  to students and practicing engineers without the need to buy additional expensive software     This manual is structured as follows     Section 2    Section 3    Section 4    Section 5    Appendix    The basic structure of both the workbook  Seepage CSMS xls  and the worksheet  used to perform the analyses will be described and the principle of operation will be  highlighted     This section will describe  step by step  how to use the basic worksheet to analyse a  new seepage problem  The resulting values of head will be used to derive  equipotentials which will be compared to those obtained using a flow net sketch     The spreadsheet tool has further been used to analyse other worked examples from  the main text  These are compared with the solutions obtained by flow net sketching  to validate the method  These examples demonstrate how different types of boundary  conditions  e g  structural elements  soil layering  may be implemented within  models     This section describes the library of different FDM nodes implemented within the  spreadsheet tool and provides further detail of the governing equations     Describes the mo
27. rmeable structural element which is partially buried   e how to model structures with combined horizontal boundaries and sheet piling   e how to derive pore pressure distributions on structural elements     The soil domain is assumed to extend approximately 5 m on either side of the spillway  Zero depth is    set at ground level  not foundation level  and the datum is set at       depth  i e  the downstream water  level   A grid spacing of 0 7 m is used  giving the FDM node layout shown in Figure 16     12    Seepage   8  8  User s Manual       15 20      10    012345    Figure 15  Example 2 2  section     ea  aa  eaa        eaa  eaa      a      aa  ea  aa  e  a eaa  2 aa  ea  eaa  eaa  aa  eaa  aa  ea  eaa  a    eaa  aa       Figure 16  FDM node allocation  Example 2 2    The resulting values of head may be found in the in the appropriate worksheet within    Seepage CSMS xls     The equipotentials derived from the FDM calculations are compared with the    2 5x10  m s  see main text     3 7x10  m s  per m length   This compares favourably with the value of 3 75x10  m s     per m length  determined from the flow net sketch     flow net sketched in the main text in Figure 17  The flow rate of water seeping underneath the spillway    is found using the method described in Section 3   gt        1 48 m and       so that q    13    Seepage CSMS8  User s Manual    Figure 17  Comparison of FDM  dashed lines  and flow net sketch  solid lines     The values of head at the nodes along t
28. sel sel        ser   24  sei verl  33  sel sos  soel         sie  is 523  525  528  53  532  533  534  535  sae 536          247  263  23  309  328  345  sel aze  seol        si ss 35  sasl 54              477  nen  ssl            soel Gl sif sel 52  523  525  szef 53         azl 533  534  836  626   183  18  207  233  256  228  239  31  336  353  368  383  336   09  aal        4  ssl 459  sex  ezel sei         493  ese  503         Gu      sil sa 24 soel 528  529       532  532  533  53    132  29  245  268  29       329         363  az 31 404  sif 427  sar  sar ssel asel        ezel 485  ss    sel sol soe  509  5 5  siel is 522  524  528  528  sos  53         532  522    inf ese  uzel 208  235  28  283  304  24 342  358  323          soi sisl 424  435  ssl ssal 51           aze   83  sel 434   39  soe         542  sil su  sal 523  525  21 soel sos  53  sal          ase  ver 193  228  254  2   3            ane  34 385  seel anl   24  33              se  see ere  sei           sol sel                  sel      52  522  524  529  5 27  529  523  sal 53  Loze  124 ve 193  223  25  275  291 sel 336  353           33  ser  nsl  2  sai ed eel   sol sex 424  sei         ese  sor  soo soel 51              is 522  524  528  522  528  529  523  529  oer  wel 152         222  243  273  236  316  335  352  seel 383  sel ns  42         sel es  esl 466   24  sel 486         sorl sool soel 51  sio        sis soo 524  525  521  528  523  523  529    Figure 24  Example 11 5    contd         
29. tribution around tunnel  all values in kPa     The flow rate is found as in the previous example  by considering the change of head  Ah  just below  the level of the excavation  From the spreadsheet  this is found to be XAA   3 30     At this level  the  water is flowing through soil 1 with permeability       so                 This gives g   3 3x10  m s  per m length      5         NODE LIBRARY    This section describes the different nodal formulae which are available within Seepage _CSM8 xls and  provides the theoretical formulation of each  These are split into four separate tables over pages 18      21 inclusive     p 18  Basic nodes for modelling impermeable boundaries and general soil nodes   p 19  Nodes for modelling soil beneath thin impermeable elements  e g  sheet piling    p 20  Nodes at the corner of an impermeable buried structure   p 21  Advanced nodes for modelling horizontal soil layer boundaries where there is a change in  permeability     17    Seepage CSMS8  User s Manual    Node type Governing equation   Representation in node library    Upper Left Corner   ULC     Upper Boundary   UB     Upper Right Corner   URC     Right Boundary   RB     Bottom Right  Corner   BRC     Bottom Boundary   BB     Bottom Left Corner   BLC     Left Boundary N 2h   h   h    LB  7 4    Internal Cells N h   h   h   h      I  4       18    Seepage   8  8  User s Manual    Node type Governing equation Representation in node library       Upper Left Pile   ULP     Intermediate     
30. within the soil continuum     Node Elevation above  index Depth Datum  z    0 0  0 5  1 0 5  1  2 1  1 5  3 1 5  2  4 2  2 5  5 2 5  3     3  3 5     3 5  4  8 4  4 5  8 45 5  10 5 55  11 5 9 B  12 B 6 5  13 6 5 7  14 7 7 5  15 73 8  1   8 8 5  17 8 5 9  18 9 95    Total head  h  m      4 5  45  45  45  45  do  45  45  45 45  45 do  45 45  45 45  45  Oo  05  05  05  05  0 51 05  0 51 05  0 5  05  05  05  05  0 5       aal 43  aal       43        43  43  aal 43        aal       as    Pep e e e ER ER ER ER es ss ET ET ET ET      onl ol os o os s s s os ED ER os ER ER ET ET  al 44 43  oz  02  02  02  oz       02            oz  02  02        06  os  os          TE FEE PIT FT EE EE FEE EEE EE EE RE          apos Loa osf osl      oal osl                          azl      azl ol    PEER                             se                al so arl      ast      32  sel sel 35      a  sal se      s        35  34              8  sel sel sel      s  35  sal 33  32       as  sel sel 32  37    EER ET ET Er ET EMET ETE  Er ET EEE      j   A         io  io                       m                w  co            co          js jw Jin                               co  co       Co    Co  eo  in        P         gt     co                                 Co Foo  Co            gt   gt   m f   o  o fio fio   je  w  co           Joo       gt  jip  m ja     o  o     Je    io      co            co       gt  ip  m jm       jo   o               co                                 o           o   o           
    
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